Đáp án:
x=-2020
Giải thích các bước giải:
\(\begin{array}{l}
\frac{{x + 7}}{{2013}} + 1 + \frac{{x + 8}}{{2012}} + 1 + \frac{{x + 9}}{{2011}} + 1 + \frac{{x + 2035}}{5} - 3 = 0\\
\to \frac{{x + 2020}}{{2013}} + \frac{{x + 2020}}{{2012}} + \frac{{x + 2020}}{{2011}} + \frac{{x + 2020}}{5} = 0\\
\to \left( {x + 2020} \right)\left( {\frac{1}{{2013}} + \frac{1}{{2012}} + \frac{1}{{2011}} + \frac{1}{5}} \right) = 0\\
\to x + 2020 = 0\\
\to x = - 2020
\end{array}\)
