c, $\frac{11}{12}$x + $\frac{3}{4}$ =$\frac{-1}{6}$
<=> $\frac{11}{12}$x = $\frac{-1}{6}$ -$\frac{3}{4}$
<=> $\frac{11}{12}$ x =$\frac{-11}{12}$
<=> x = -1
Vậy x=-1
d, |x-$\frac{1}{3}$ |=$\frac{5}{6}$
<=> +, x - $\frac{1}{3}$ =$\frac{5}{6}$ <=> x= $\frac{7}{6}$
<=> +, x - $\frac{1}{3}$ =$\frac{-5}{6}$ <=> x=$\frac{1}{2}$
e, (x -$\frac{5}{8}$ ) . $\frac{5}{18}$ =$\frac{-15}{36}$
<=> x- $\frac{5}{8}$ = $\frac{-15}{36}$ : $\frac{5}{18}$
<=> x -$\frac{5}{5}$ = $\frac{-3}{2}$
<=> x = $\frac{-3}{2}$ +$\frac{5}{8}$
<=> x = $\frac{-7}{8}$
Vậy x= $\frac{-7}{8}$
g, ⇔$\frac{x}{5}$ + $\frac{2}{5}$ =$\frac{16}{5}$
<=> $\frac{x}{5}$ = $\frac{16}{5}$ - $\frac{2}{5}$
<=> $\frac{x}{5}$ =$\frac{14}{5}$
<=> x = 14
Vậy x bằng 14
