Lời giải chi tiết:
`C29:Mg+2HCl->MgCl_2+H_2`
`n_{Mg}=(2,4)/24=0,1(mol)`
`mct_{HCl}=50.7,3%=3,65(g)`
`n_{HCl}=(3,65)/(36,5)=0,1(mol)`
`n_{Mg}=0,1(mol)>n_{HCl}=(0,1)/2=0,05(mol)`
$Mg\ du$
`n_{MgCl_2}=1/2 .0,1=0,05(mol)`
`m_{MgCl_2}=0,05.(24+35,5.2)=4,75(g)`
`mdd_{spu}=2,4+50-0,1.2=52,2(g)`
`%m_{MgCl_2}=(4,75)/(52,2%)=9,1%`
`C30:Mg+2HCl->MgCl_2+H_2`
`n_{Mg}=(2,4)/24=0,1(mol)`
`mct_{HCl}=50.7,3%=3,65(g)`
`n_{HCl}=(3,65)/(36,5)=0,1(mol)`
`n_{Mg}=0,1(mol)>n_{HCl}=(0,1)/2=0,05(mol)`
`n_{MgCl_2}=1/2 .0,1=0,05(mol)`
`m_{MgCl_2}=0,05.(24+35,5.2)=4,75(g)`
