`a) |x - 1,7| = 2,3`
`=>`\(\left[ \begin{array}{l}x - 1,7 = 2,3\\x - 1,7 = -2,3\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x= 3\\x=-0,6\end{array} \right.\)
`b) | x + 3/4| -1/3 = 0`
`=> | x + 3/4| = 0 + 1/3 = 1/3`
`=>`\(\left[ \begin{array}{l}x + 3/4 = 1/3\\x + 3/4 = -1/3\end{array} \right.\)
`=>`\(\left[ \begin{array}{l}x=-5/12\\x=-13/12\end{array} \right.\)
Vậy `x ∈ { -5/12 ; -13/12 }`