ĐKXĐ : `x \le 4/3`
`sqrt{4-3x} = 8`
`<=> (sqrt{4-3x})^2 = 8^2`
`<=> 4 - 3x = 64`
`<=> 3x = -60`
`<=> x = -20(TMĐK)`
Vậy `S = {-20}`
ĐKXĐ : `x \ge 2`
`sqrt{4x-8} - 12sqrt{(x-2)/9} = -1`
`⇔ sqrt{4(x-2)} - 12 * sqrt(x-2)/3 = -1`
`⇒ 2sqrt{x-2} - 4sqrt{x-2} = -1`
`⇔ -2sqrt{x-2} = -1`
`⇔ sqrt{x-2} = 1/2`
`⇔ (sqrt{x-2})^2 = (1/2)^2`
`⇔ x - 2 = 1/4`
`⇔ x = 9/4(TMĐK)`
Vậy `S = {9/4}`
