Đáp án:
\(\begin{array}{l}
b)\\
{C_\% }{H_2}S{O_4} = 3,92\% \\
c)\\
{V_{{H_2}}} = 4,48l
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
Fe + {H_2}S{O_4} \to FeS{O_4} + {H_2}\\
b)\\
{n_{Fe}} = \dfrac{{11,2}}{{56}} = 0,2\,mol\\
{n_{{H_2}S{O_4}}} = {n_{Fe}} = 0,2\,mol\\
{C_\% }{H_2}S{O_4} = \dfrac{{0,2 \times 98}}{{500}} \times 100\% = 3,92\% \\
c)\\
{n_{{H_2}}} = {n_{Fe}} = 0,2\,mol\\
{V_{{H_2}}} = 0,2 \times 22,4 = 4,48l
\end{array}\)
\(\begin{array}{l}
{m_{{\rm{ddspu}}}} = 11,2 + 500 - 0,2 \times 2 = 510,8g\\
{n_{FeS{O_4}}} = {n_{Fe}} = 0,2\,mol\\
{C_\% }FeS{O_4} = \dfrac{{0,2 \times 152}}{{510,8}} \times 100\% = 5,95\%
\end{array}\)
