Đáp án+Giải thích các bước giải:
`e) (x+1/2).(2/3-2x)=0`
`<=>`\(\left[ \begin{array}{l}x+\dfrac{1}{2}=0\\\dfrac{2}{3}-2x=0\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=-\dfrac{1}{2}\\2x=\dfrac{2}{3}\end{array} \right.\)
`<=>`\(\left[ \begin{array}{l}x=-\dfrac{1}{2}\\x=\dfrac{1}{3}\end{array} \right.\)
Vậy `x∈{-1/2; 1/3}`