ho hệ phương trình:
\left\{{}\begin{matrix}\left(3x-1\right)\left(2y+2\right)=\left(x+1\right)\left(6y-1\right)\\ \left(x+2\right)\left(4y+1\right)=\left(2x-1\right)\left(2y+2\right)\end{matrix}\right.
{
(3x−1)(2y+2)=(x+1)(6y−1)
(x+2)(4y+1)=(2x−1)(2y+2)
Loga
Sinh Học lớp 12
