Đáp án:
2)
a)
\(pH = 2\)
b)
\(pH = 11\)
Giải thích các bước giải:
\(\begin{array}{l}
1)\\
A{l_2}{(S{O_4})_3} \to 2A{l^{3 + }} + 3S{O_4}^{2 - }\\
BaS{O_4} \to B{a^{2 + }} + S{O_4}^{2 - }\\
C{H_3}COOH \leftrightarrows C{H_3}{\rm{CO}}{{\rm{O}}^ - } + {H^ + }\\
BaC{l_2} \to B{a^{2 + }} + 2C{l^ - }\\
AgCl \to A{g^ + } + C{l^ - }\\
Fe{(OH)_3} \leftrightarrows F{e^{3 + }} + 3O{H^ - }\\
KOH \to {K^ + } + O{H^ - }\\
HN{O_3} \to {H^ + } + N{O_3}^ - \\
2)\\
a)\\
{\rm{[}}{H^ + }{\rm{] = }}{{\rm{C}}_{{M_{HN{O_3}}}}} = 0,01M\\
pH = - \log (0,01) = 2\\
b)\\
{\rm{[}}O{H^ - }{\rm{]}} = {C_{{M_{NaOH}}}} = {10^{ - 3}}M\\
pOH = - \log ({10^{ - 3}}) = 3\\
pH = 14 - 3 = 11\\
3)\\
a)\\
MgS{O_4} + 2NaOH \to Mg{(OH)_2} + N{a_2}S{O_4}\\
M{g^{2 + }} + 2O{H^ - } \to Mg{(OH)_2}\\
b)\\
CaC{O_3} + 2HN{O_3} \to Ca{(N{O_3})_2} + {H_2}O + C{O_2}\\
2{H^ + } + CaC{O_3} \to C{a^{2 + }} + {H_2}O + C{O_2}\\
c)\\
KCl + NaOH \text{ không xảy ra phản ứng}
\end{array}\)
