Zn + 2HCl ==> ZnCl2 + H2
0,1...........................0,1..........0,1
ZnO + 2HCl ==> ZnCl2 + H2O
0,05.......................0,05
Ta có: nH2= 2,24/22,4= 0,1 (mol)
==> nZn=nH2= 0,1 (mol)
==> mZn= 0,1x65= 6,5 (g)
==> mZnO= 10,55-6,5= 4,05 (g)
nZnO= 4,05/81= 0,05 (mol)
Bạn tự tính % nhé
b) nZnCl2= 0,1 + 0,05= 0,15 (mol)
==> CmZnCl2= n/V= 0,15/0,2= 0,75M