Đáp án:
`C%_{HCl}=1,722%`
`C%_{CuCl_2}=9,552%`
Giải thích các bước giải:
`CuO+2HCl->CuCl_2+H_2O`
`n_{CuO}=12/80=0,15(mol)`
`m_{HCl}=200.7,3%=14,6(g)`
`n_{HCl}=(14,6)/(36,5)=0,4(mol)`
`(0,15)/1<(0,4)/2=>HCl` dư
`n_{HClpư}=2n_{CuO}=0,3(mol)`
`n_{HCldư}=0,4-0,3=0,1(mol)`
`n_{CuCl_2}=n_{CuO}=0,15(mol)`
`m_{ddspư}=12+200=212(g)`
`C%_{HCl}=(0,1.36,5)/212 .100=1,722%`
`C%_{CuCl_2}=(0,15.135)/212 .100=9,552%`