$n_{H_2}=3,36/22,4=0,15mol$
$a/2K+2HCl\to 2KCl+H_2$
$Zn+2HCl\to ZnCl_2+H_2$
b/Gọi $n_K=a;n_{Zn}=b$
Ta có :
m_{hh}=39a+65b=19,5
n_{H_2}=0,5a+b=0,15
Ta có hpt :
$\left\{\begin{matrix}
39a+65b=19,5 & \\
0,5a+b=0,15 &
\end{matrix}\right.$
$⇔\left\{\begin{matrix}
a=1,5 & \\
y=-0,6 &
\end{matrix}\right.$
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