`#AkaShi`
PTHH:
`2Al+6HCl -> 2AlCl_3+3H_2↑`
`a)`
`->n_{Al}=(m_{Al})/(M_{Al})=(5,4)/27=0,2\ (mol)`
Đổi: `300m=0,3\ (l)`
`->n_{HCl}=0,3xx0,3=0,09\ (mol)`
`Xets hết dư:
`->n_{Al}=(0,2)/2 > n_{HCl}=(0,09)/6\ (mol)`
`->Al` dư ; `HCl` hết
`->n_{Al\ pư}=2/6xxn_{HCl}=0,09xx2/6=0,03\ (mol)`
`->n_{Al\ dư}=0,2-0,03=0,17\ (mol)`
`->m_{Al\ dư}=0,17xx27=4,59\ (g)`
`\text{_________________________________}`
`b)`
`->n_{H_2}=3/6xxn_{HCl}=0,09xx3/6=0,045\ (mol)`
`->m_{dd}=5,4+(0,09xx36,5)-(0,045xx2)=8,595\ (mol)`
`->n_{AlCl_3}=2/6xxn_{HCl}=0,09x2/6=0,03\ (mol)`
`->C%_{AlCl_3}=(0,03xx133,5)/(8,595)xx100%=46,6%`
`\text{_________________________________}`
`c)`
`->n_{H_2}=0,045\ (mol)`
`->m_{H_2}=n_{H_2}xxM_{H_2}=0,045xx2=0,09\ (g)`
