Em tham khảo nha :
\(\begin{array}{l}
N{a_2}O + {H_2}O \to 2NaOH\\
NaOH + HCl \to NaCl + {H_2}O\\
{n_{N{a_2}O}} = \dfrac{{6,2}}{{62}} = 0,1mol\\
{n_{NaOH}} = 2{n_{N{a_2}O}} = 0,2mol\\
{m_{NaOH}} = 0,2 \times 40 = 8g\\
C{\% _{NaOH}} = \dfrac{8}{{100 + 6,2}} \times 100\% = 7,53\% \\
{n_{HCl}} = {n_{NaOH}} = 0,2mol\\
{m_{HCl}} = 0,2 \times 36,5 = 7,3g\\
{m_{ddHCl}} = \dfrac{{7,3 \times 100}}{{10}} = 73g\\
{n_{NaCl}} = {n_{NaOH}} = 0,2mol\\
{m_{NaCl}} = 0,2 \times 58,5 = 11,7g\\
C{\% _{NaCl}} = \dfrac{{11,7}}{{6,2 + 100 + 73}} \times 100\% = 6,53\%
\end{array}\)