Đáp án:
\(\begin{array}{l}
b)\\
{V_{{H_2}}} = 2,24l\\
c)\\
{C_{{M_{ZnC{l_2}}}}} = 1M
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
Zn + 2HCl \to ZnC{l_2} + {H_2}\\
b)\\
{n_{Zn}} = \frac{m}{M} = \dfrac{{6,5}}{{65}} = 0,1mol\\
{n_{{H_2}}} = {n_{Zn}} = 0,1mol\\
{V_{{H_2}}} = 0,1 \times 22,4 = 2,24l\\
c)\\
{n_{ZnC{l_2}}} = {n_{Zn}} = 0,1mol\\
{C_{{M_{ZnC{l_2}}}}} = \dfrac{n}{V} = \dfrac{{0,1}}{{0,1}} = 1M
\end{array}\)