$\begin{gathered}
68g\,\left\{ \begin{gathered}
CuO \hfill \\
ZnO \hfill \\
\end{gathered} \right.\, + \,NaO{H_{du}} \to N{a_2}Zn{O_2} + \,{H_2}O\, + \,Cu{O_{khong\,pu}} \hfill \\
{n_{HCl}} = \frac{{{m_{{\text{dd}}}} \times C\% }}{{M \times 100\% }} = \frac{{8 \times 36.5}}{{36.5 \times 100}} = 0.08\,mol \hfill \\
\end{gathered}$
Chất rắn là CuO
$\begin{gathered}
uO\, + \,2HCl \to CuC{l_2} + {H_2}O \hfill \\
0.04 \leftarrow 0.08\,\,\,(mol) \hfill \\
\to \left\{ \begin{gathered}
{m_{CuO}} = 0.04 \times 80 = 3.2g \hfill \\
{m_{ZnO}} = 68 - 3.2 = 64.8g \hfill \\
\end{gathered} \right. \to \left\{ \begin{gathered}
\% CuO = 4.7\% \hfill \\
\% ZnO = 100\% - 4.7\% = 95.3\% \hfill \\
\end{gathered} \right. \hfill \\
{n_{ZnO}} = 64.8/81 = 0.8\,mol \hfill \\
ZnO\, + \,2NaOH\, \to N{a_2}Zn{O_2} + {H_2}O \hfill \\
0.8\,mol\,\,\,\xrightarrow{{}}\,\,\,\,\,\,\,0.8\,mol \hfill \\
\end{gathered} $
Muối gồm $CuC{l_2}$ và $N{a_2}Zn{O_2}$
$\left\{ \begin{gathered}
{m_{CuC{l_2}}} = 0.04 \times 135 = 5.4g \hfill \\
{m_{N{a_2}Zn{O_2}}} = 0.8 \times 143 = 114.4g \hfill \\
\end{gathered} \right.$
