Đáp án đúng: D
Giải chi tiết:\(\begin{gathered} \mathop {Mg}\limits^0 \to \mathop {Mg}\limits^{ + 2} + 2e \hfill \\ 0,4\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,8(mol) \hfill \\ \mathop {2N}\limits^{ + 5} + 2(5 - n)e \to \mathop {2N}\limits^{ + n} ({N_2}{O_n}) \hfill \\ \,\,\,\,\,\,\,\,\,\,0,2\left( {5 - n} \right)\,\,\,\,\,\,\,0,2\,\,\,0,1\,\,\,\,\,\,(mol) \hfill \\ \end{gathered} \)
Theo ĐLBT electron ta có: 0,8 = 0,2.(5-n) => n=1. Vậy Z là N2O.