Đáp án:
c) 9%
Giải thích các bước giải:
3,36l H2 mới đúng nha em
\(\begin{array}{l}
a)\\
2C{H_3}COOH + Mg \to {(C{H_3}COO)_2}Mg + {H_2}\\
2C{H_3}COOH + Zn \to {(C{H_3}COO)_2}Zn + {H_2}\\
b)\\
n{H_2} = \dfrac{V}{{22,4}} = \dfrac{{3,36}}{{22,4}} = 0,15\,mol\\
hh:Mg(a\,mol),Zn(b\,mol)\\
24a + 65b = 11,3\\
0,5a + 0,5b = 0,15\\
\Rightarrow a = 0,2;b = 0,1\\
\% mMg = \dfrac{{0,2 \times 24}}{{11,3}} \times 100\% = 42,48\% \\
\% mZn = 100 - 42,48 = 57,52\% \\
c)\\
nC{H_3}COOH = 2n{H_2} = 0,3\,mol\\
C\% C{H_3}COOH = \dfrac{{0,3 \times 60}}{{200}} \times 100\% = 9\% \\
m{\rm{dd}}spu = 11,3 + 200 - 0,15 \times 2 = 211g\\
C\% {(C{H_3}COO)_2}Mg = 13,46\% \\
C\% {(C{H_3}COO)_2}Zn = 8,67\%
\end{array}\)