Đáp án:
Gọi KL là R
$nH_{2}=\frac{5,6}{22,4}=0,25$
$2nR=2nH_{2}⇒nR=0,25$
$MR=\frac{16,25}{0,25}=65(Zn)$
$nHCl=2nH_{2}=0,25.2=0,5$
$mddHCl=\frac{0,5.36,5}{18,25\%}=100g$
$VddHCl=\frac{100}{1,2}=83,33ml=0,083lit$
$CMHCl=\frac{0,5}{0,083}=6M$
$nZn=nZnCl_{2}=0,25$
$C\%ZnCl_{2}=\frac{0,25.136}{100+16,25-0,25.2}.100=29,37\%$