Em tham khảo nha :
\(\begin{array}{l}
a)\\
Mg + {H_2}S{O_4} \to MgS{O_4} + {H_2}\\
{n_{Mg}} = \dfrac{{2,4}}{{24}} = 0,1mol\\
{n_{{H_2}S{O_4}}} = {n_{Mg}} = 0,1mol\\
{m_{{H_2}S{O_4}}} = 0,1 \times 98 = 9,8g\\
b)\\
{n_{MgS{O_4}}} = {n_{Mg}} = 0,1mol\\
{m_{MgS{O_4}}} = 0,1 \times 120 = 12g\\
c)\\
{n_{{H_2}}} = {n_{Mg}} = 0,1mol\\
{V_{{H_2}}} = 0,1 \times 22,4 = 2,24l
\end{array}\)