Pt Al2+6HCl ------) 2AlCl3+3H2
2X 3X
Fe+2HCl--------) FeCl2+H2
Y Y
b)nH2=0.8
gọi nAl=2x, nFe=y ta có
hpt$\left \{ {{2.27x+56y=22} \atop {3x+y=0.8}} \right.$ $\left \{ {{2.27x+56y=22} \atop {3x+y=0.8}} \right.$
sau đó tìm x,y$\left \{ {{2.27x+56y=22} \atop {3x+y=0.8}} \right.$