Đáp án:
a. `V_{H_2}=8,96\ \text {l`
b. \(\text C_{\text M \ \text{CH}_3\text{COOH}}=1,6\ \text M\)
Giải thích các bước giải:
a. \(Zn+2CH_3COOH\to {(CH_3COO)}_2Zn+H_2\)
\(n_{Zn}=\dfrac{26}{65}=0,4\ \text{mol}\\ n_{H_2}=n_{Zn}=0,4\ \text{mol}\\\to \text V_{H_2}=0,4\times 22,4=8,96\ \text l\)
b. \(n_{CH_3COOH}=2n_{Zn}=0,4\times 2=0,8\ \text{mol}\\\to \text C_{\text M \ \text{CH}_3\text{COOH}}=\dfrac{0,8}{0,5}=1,6\ \text M\)