Đáp án:
\(\begin{array}{l}
\% Zn = 70,65\% \\
\% ZnO = 29,35\% \\
{m_{{\rm{dd}}HN{O_3}}} = 630g
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
3Zn + 8HN{O_3} \to 3Zn{(N{O_3})_2} + 2NO + 4{H_2}O\\
ZnO + 2HN{O_3} \to Zn{(N{O_3})_2} + {H_2}O\\
{n_{NO}} = \dfrac{{4,48}}{{22,4}} = 0,2mol\\
{n_{Zn}} = \dfrac{3}{2}{n_{NO}} = 0,3mol\\
{m_{Zn}} = 0,3 \times 65 = 19,5g\\
{m_{ZnO}} = 27,6 - 19,5 = 8,1g\\
\% Zn = \dfrac{{19,5}}{{27,6}} \times 100\% = 70,65\% \\
\% ZnO = 100 - 70,65 = 29,35\% \\
{n_{ZnO}} = \dfrac{{8,1}}{{81}} = 0,1mol\\
{n_{HN{O_3}}} = \dfrac{8}{3}{n_{Zn}} + 2{n_{ZnO}} = 1mol\\
{m_{HN{O_3}}} = 1 \times 63 = 63g\\
{m_{{\rm{dd}}HN{O_3}}} = \dfrac{{63 \times 100}}{{10}} = 630g
\end{array}\)