Đáp án:
\({m_{Zn}} = 19,5{\text{ gam}}\)
\({\text{C}}{{\text{\% }}_{HCl}} = 10,95\% \)
Giải thích các bước giải:
Phản ứng xảy ra:
\(Zn + 2HCl\xrightarrow{{}}ZnC{l_2} + {H_2}\)
Ta có:
\({n_{Zn}} = {n_{{H_2}}} = \frac{{6,72}}{{22,4}} = 0,3{\text{ mol}} \to {{\text{n}}_{HCl}} = 2{n_{{H_2}}} = 0,6{\text{ mol}}\)
\( \to {m_{Zn}} = 0,3.65 = 19,5{\text{ gam}}\)
\({m_{HCl}} = 0,6.36,5 = 21,9{\text{ gam}} \to {\text{C}}{{\text{\% }}_{HCl}} = \frac{{21,9}}{{200}}.100\% = 10,95\% \)