Đáp án:
Giải thích các bước giải:
$a)(6x+1)^2+(6x-1)^2-2(1+6x)(6x-1)$
$=(6x+1)^2-2(6x+1)(6x-1)+(6x-1)^2$
$=[(6x+1)-(6x-1)]^2$
$=(6x+1-6x+1)^2$
$=2^2$
$=4$
$b) x(2x^2-3)-x^2(5x+1)+x^2$
$=2x^3-3x-5x^3-x^2+x^2$
$=-3x^3-3x$
$c) 3(2^2+1)(2^4+1)(2^8+1)(2^{16}+1)$
$=(2^2-1)(2^4+1)(2^8+1)(2^{16}+1)$
$=(2^4-1)(2^4+1)(2^8+1)(2^{16}+1)$
$=(2^8-1)(2^8+1)(2^{16}+1)$
$=(2^{16}-1)(2^{16}+1)$
$=2^{32}-1$
$d) 3x(x-2)-5x(1-x)-8(x^2-3)$
$=3x^2-6x-5x+5x^2-8x^2+24$
$=-11x+24$