Đáp án:
Giải thích các bước giải:
a)
$2CH3COOH+2Na-->2CH3COONa+H2$
$2C2H5OH+2Na--->2C2H5ONa+H2$
$2CH3COOH+Na2CO3-->2CH3COONa+H2O+CO2$
b)
$nH2=0,448/22,4=0,02(mol)$
$nCO2=0,336/22,4=0,015(mol)$
$nCH3COOH=2nCO2=0,03(mol)$
=>$mCH3COOH=0,03.60=1,8(g)$
$nH2(1)=1/2nCH3COOH=0,015(mol)$
=>$nH2(2)=0,02-0,015=0,005(mol)$
$nC2H5OH=2$nH2=0,01(mol)$
=>$mC2H5OH=0,01.46=0,46(g)$
=>$m=0,46+1,8=2,26(g)$
c)
%$mC2H5OH=0,46/2,26.100$%$=20,35$%
=>%$mCH3COOH=100-20,35=76,65$%
d)
$CH3COOH+C2H5OH-->H2O+CH3COOC2H5$
$nCH3COOH>nC2H5OH$
=>CH3COOH dư
$nCH3COOC2H5=nC2H5OH=0,01(mol)$
=>$mCH3COOC2H5=0,01.76=0,76(g)$
$nH2O=nC2H5OH=0,01(mol)$
=>$mH2O=0,01.18=0,18(g)$