Đáp án:
`%m_{CO}=51,124%`
`%m_{O_2}=10,861%`
`%m_{N_2}=38,015%`
Giải thích các bước giải:
Gọi `a,b` là `n_{CO},n_{kk}`
`\overlineM_A=\frac{28a+29b}{a+b}=14,24.2=28,48`
`⇔28a+29b=28,48a+28,48b`
`⇔0,52b=0,48a`
`⇔a/b={13}/{12}`
`%m_{CO}=\frac{13.28}{13.28+12.29}.100=51,124%`
`%m_{kk}=100%-51,124%=48,876%`
`%m_{O_2}`$/kk$`=\frac{32.1}{32.1+28.4}.100=22,222%`
`%m_{N_2}`$/kk$`=100%-22,222%=77,778%`
`%m_{O_2}=22,222%.48,876=10,861%`
`%m_{N_2}=77,778%.48,876=38,015%`
`#Devil`