Đáp án:
Giải thích các bước giải:
a) ${\overline M _{hh}} = 24.2 = 48;{\overline M _{hhsau}} = 30.2 = 60$
$\begin{gathered} \begin{array}{*{20}{c}} {S{O_2}:64}&{}&{}&{}&{16} \\ {}& \searrow &{}& \nearrow &{} \\ {}&{}&{48}&{}&{} \\ {}& \nearrow &{}& \searrow &{} \\ {{O_2}:32}&{}&{}&{}&{16} \end{array} \Rightarrow \dfrac{{{n_{S{O_2}}}}}{{{n_{{O_2}}}}} = \dfrac{1}{1} \hfill \\ \Rightarrow \% {V_{S{O_2}}} = \% {V_{{O_2}}} = 50\% \hfill \\ \end{gathered} $
$\begin{gathered} {\text{ }}2S{O_2} + {O_2}\overset {} \leftrightarrows 2S{O_3} \hfill \\ \hfill \\ \end{gathered} $
Bđ 1 1
Pư 2x x 2x
Sau: 1-2x 1-x 2x
$\sum {{n_{hhsau}}} = 2 - x$
Bảo toàn khối lượng:
$\begin{gathered}
{m_{truoc}} = {m_{sau}} \Leftrightarrow 2.48 = 60.(2 - x) \Rightarrow x = 0,4 \hfill \\
\Rightarrow {n_{S{O_2}}} = 0,2;{n_{{O_2}}} = 0,6;{n_{S{O_3}}} = 0,8;{n_{hhsau}} = 1,6 \hfill \\
\Rightarrow \% {V_{S{O_2}}} = \dfrac{{0,2}}{{1,6}}.100\% = 12,5\% \hfill \\
\% {V_{{O_2}}} = \dfrac{{0,6}}{{1,6}}.100\% = 37,5\% \hfill \\
\% {V_{S{O_3}}} = 100 - 12,5 - 37,5 = 50\% \hfill \\
\end{gathered} $
b)
$\begin{gathered}
\% {V_{S{O_2}pu}} = \dfrac{{0,4.2}}{1}.100\% = 80\% \hfill \\
\% {V_{{O_2}pu}} = \dfrac{{0,4}}{1}.100\% = 40\% \hfill \\
\end{gathered} $
