Đặt : CTHH : RCOOR'
nO2 = 0.975 mol
nCO2 = 0.8 mol
BTKL :
mH2O = 15.7 + 0.975*32 - 0.8*44 = 11.7 g
nH2O = 0.65 mol
BTNT :
nO (Y) = 2nCO2 + nH2O - 2nO2 = 0.3 mol
=> nY = 0.15 mol
M = 15.7/0.15 = 104.67
=> R + R' = 60.67
M ancol = 7.6/0.15 = 50.67
=> R + 17 = 50.67
=> R = 33.67
=> R' = 27
CT : C3H7OH , C2H5OH
CT este : A : CH2 = CH - COOC2H5
B: CH2 = CH - COOC3H7
Đặt :
nA = x mol
nB = y mol
<=> x + y = 0.15
100x + 114y = 15.7
=> x = 0.1
y = 0.05
%A = 0.1*100/15.7 * 100% = 63.69%