Đáp án:
Em tham khảo nha
Giải thích các bước giải:
\(\begin{array}{l}
2KMn{O_4} \xrightarrow{t^0} {K_2}Mn{O_4} + Mn{O_2} + {O_2}\\
2Cu + {O_2} \xrightarrow{t^0} 2CuO\\
CuO + 2HCl \to CuC{l_2} + {H_2}O\\
CuC{l_2} + 2AgN{O_3} \to Cu{(N{O_3})_2} + 2AgCl\\
2AgCl \xrightarrow{as} 2Ag + C{l_2}\\
2NaBr + C{l_2} \to 2NaCl + B{r_2}\\
2NaI + B{r_2} \to 2NaBr + {I_2}\\
C{l_2} + 2NaOH \to NaCl + NaClO + {H_2}O\\
2NaCl + 2{H_2}O \to 2NaOH + C{l_2} + {H_2}\\
NaCl + AgN{O_3} \to AgCl + NaN{O_3}\\
2NaCl + {H_2}S{O_4} \to N{a_2}S{O_4} + 2HCl\\
HCl + NaOH \to NaCl + {H_2}O\\
Fe + 2HCl \to FeC{l_2} + {H_2}\\
S + {O_2} \xrightarrow{t^0} S{O_2}\\
S{O_2} + 2{H_2}S \to 3S + 2{H_2}O\\
S + {H_2} \xrightarrow{t^0} {H_2}S\\
2{H_2}S + 3{O_2} \xrightarrow{t^0} 2{H_2}O + 2S{O_2}\\
S{O_2} + B{r_2} + 2{H_2}O \to {H_2}S{O_4} + 2HBr\\
{H_2}S{O_4} + 3{H_2}S \to 4S + 4{H_2}O\\
S + {O_2} \xrightarrow{t^0} S{O_2}\\
2S{O_2} + {O_2} \xrightarrow{t^0,V_2O_5} 2S{O_3}\\
S{O_3} + {H_2}O \to {H_2}S{O_4}\\
F{e_2}{O_3} + 3{H_2}S{O_4} \to F{e_2}{(S{O_4})_3} + 3{H_2}O\\
F{e_2}{(S{O_4})_3} + 3BaC{l_2} \to 2FeC{l_3} + 3BaS{O_4}\\
4Fe{S_2} + 11{O_2} \xrightarrow{t^0} 2F{e_2}{O_3} + 8S{O_2}\\
S + Fe \xrightarrow{t^0} FeS\\
FeS + 2HCl \to FeC{l_2} + {H_2}S\\
Fe + {H_2}S{O_4} \to FeS{O_4} + {H_2}\\
{H_2}S + 4B{r_2} + 4{H_2}O \to {H_2}S{O_4} + 8HBr
\end{array}\)
