Đáp án:$\frac{25}{32}$
Giải thích các bước giải:
\(\frac{5}{2.5}+\frac{5}{5.8}+......+\frac{5}{29.32}\)
\(=\frac{5}{3}.\left(\frac{3}{2.5}+\frac{3}{5.8}+.........+\frac{3}{29.32}\right)\)
\(=\frac{5}{3}.\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+........+\frac{1}{29}-\frac{1}{32}\right)\)
\(=\frac{5}{3}.\left(\frac{1}{2}-\frac{1}{32}\right)=\frac{5}{3}.\frac{15}{32}\)=$\frac{25}{32}$
Cho mk CTLHN nha =))
