Giải thích các bước giải:
Ta có:
\(\begin{array}{l}
285,\\
*)\\
9 = {3^2}\\
24 = {2^3}.3\\
\Rightarrow BCNN\left( {9;24} \right) = {2^3}{.3^2} = 72\\
*)\\
12 = {2^2}.3\\
52 = {2^2}.13\\
\Rightarrow BCNN\left( {12;52} \right) = {2^2}.3.13 = 156\\
286,\\
*)\\
14 = 2.7\\
21 = 3.7\\
56 = {2^3}.7\\
\Rightarrow BCNN\left( {14;21;56} \right) = {2^3}.3.7 = 168\\
*)\\
16 = {2^4}\\
34 = 2.17\\
104 = {2^3}.13\\
\Rightarrow BCNN\left( {16;34;104} \right) = {2^4}.13.17 = 3536
\end{array}\)
