Đáp án:
b) 12,8g
c) 16,7g
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
{C_2}{H_5}OH + {O_2} \xrightarrow{\text{ lên men }} C{H_3}COOH + {H_2}O\\
b)\\
{V_{{C_2}{H_5}OH}} = 200 \times \dfrac{8}{{100}} = 16ml\\
{m_{{C_2}{H_5}OH}} = 16 \times 0,8 = 12,8g\\
c)\\
{n_{{C_2}{H_5}OH}} = \dfrac{{12,8}}{{46}} = \dfrac{{32}}{{115}}mol\\
{n_{C{H_3}COOH}} = {n_{{C_2}{H_5}OH}} = \dfrac{{32}}{{115}}\,mol\\
{m_{C{H_3}COOH}} = \dfrac{{32}}{{115}} \times 60 = 16,7g
\end{array}\)