Khi trùng ngưng a gam axit ԑ-aminocaproic (H = 80%) thu được m gam tơ capron và 14,4 gam H2O. Giá trị của m là nH2N-[CH2]5-COOH → (-NH-[CH2]5-CO-)n + nH2O nH2O = 0,8 mol → nmắt xích polime = 0,8 mol → mpolime = mmắt xích polime = 0,8.113 = 90,4 gam bài này sao ko nhận chia hiệu suất vậy?

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