Em tham khảo!
$\text{Đồng(II) Clorua: CuCl2}$
$\rightarrow$ $\text{Cu=64}$
$\rightarrow$ $\text{Cl= 35,5}$
$\leftrightarrow$ $\text{CuCl2=64+(35,5.2)=135}$
$\rightarrow$ $\text{4CuCl2=135.4=540}$
$\leftrightarrow$ $\text{Chọn A) 540}$
#TRANPHAMGIABAO