Đáp án đúng: C
Giải chi tiết:\(\begin{gathered} F{e_3}{O_4} + {\text{ 4}}{H_2}\xrightarrow{{}}3Fe\, + \,4{H_2}O \hfill \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,0,045 \to 0,06 \hfill \\ Fe\,\,\, + \,\,\,2HCl\xrightarrow{{}}FeC{l_2} + {H_2} \hfill \\ 0,045\,\,\,\,\,\,\,\,\,\,\,\,\,\xleftarrow{{}}\,\,\,\,\,\,\,\,\,\,\,\,\,0,045 \hfill \\ {n_{{H_2}}} = \,1,008:22,4\,\, = \,\,0,045\,\,(mol) \hfill \\ = > {m_{{H_2}O}} = 0,06.18 = 1,08(g) \hfill \\ \end{gathered} \)
Đáp án C