10)
nCl2= 0,05 mol
2NaOH+ Cl2 -> NaCl+ NaClO+ H2O
=> nNaOH= 0,1 mol; nNaCl= nNaClO= 0,05 mol
V NaOH= 0,1/1= 0,1l= 100 ml
CM NaCl= CM NaClO= 0,05/0,1= 0,5M
11)
2M+ 3Cl2 -> 2MCl3
nM= nMCl3
<=> 10,8/M= 53,4/(M+ 106,5)
<=> 53,4M= 10,8(M+ 106,5)
<=> M=27. Vậy M là nhôm (Al)