`Al, CuO;` oxit `Fe => Al2O3; Al; Fe; Cu`
`Al + NaOH + H2O -> NaAlO2 + (3)/(2) H2`
`Al2O3 + 2NaOH -> 2NaAlO2 + H2O`
Ta thấy: `nAl = nNaOH = 1,2`
` => mhh = mAl + mCu + mFe + mO`
`m = 1,2.27 + 28 + m.13,71%`
`=> m = 70`
` => mO= 9,597 => nO=0,6` (mol)
`=> nAl2O3 = 0,2` (mol)
`=> nAl = 1,2-0,2.2=0,8` (mol)
`=> nH2 = 0,8.(3)/(2)=1,2` (mol)
` => VH2 = 26,88` (l)