1)
Quặng manhetit chứa \(Fe_3O_4\)
Sơ đồ:
\(F{e_3}{O_4}\xrightarrow{{93\% }}3Fe\)
Ta có:
\({m_{F{e_3}{O_4}}} = 400.80\% = 320{\text{ tấn}}\)
\( \to {n_{F{e_3}{O_4}}} = \frac{{320}}{{56.3 + 16.4}} = \frac{{320}}{{232}}\)
\( \to {n_{Fe{\text{ lt}}}} = 3{n_{F{e_3}{O_4}}} = \frac{{320}}{{232}}.3 = \frac{{120}}{{29}}\)
Nhưng hiệu suất phản ứng chỉ là 93%
\( \to {n_{Fe}} = \frac{{120}}{{29}}.93\% = \frac{{558}}{{145}}\)
\( \to {m_{Fe}} = \frac{{558}}{{145}}.56 = 215,5{\text{ tấn}}\)
\( \to {m_{gang}} = \frac{{{m_{Fe}}}}{{95\% }} = \frac{{215,5}}{{95\% }} = 226,8421{\text{ tấn}}\)
2)
Phản ứng xảy ra:
\(2A + C{l_2}\xrightarrow{{{t^o}}}2ACl\)
Ta có:
\({n_A} = \frac{{9,2}}{A} = {n_{ACl}} = \frac{{23,4}}{{A + 35,5}} \to A = 23 \to Na\)
3)
Các phản ứng xảy ra:
\(Mg + {H_2}S{O_4}\xrightarrow{{}}MgS{O_4} + {H_2}\)
\(Fe + {H_2}S{O_4}\xrightarrow{{}}FeS{O_4} + {H_2}\)
\(Zn + {H_2}S{O_4}\xrightarrow{{}}ZnS{O_4} + {H_2}\)
Ta có:
\({n_{{H_2}}} = \frac{{8,96}}{{22,4}} = 0,4{\text{ mol = }}{{\text{n}}_{{H_2}S{O_4}}}\)
BTKL:
\({m_{kl}} + {m_{{H_2}S{O_4}}} = {m_{muối}} + {m_{{H_2}}}\)
\( \to 16,9 + 0,4.98 = {m_{muối}} + 0,4.2\)
\( \to {m_{muối}} = 55,3{\text{ gam}}\)