Đáp án:
$\begin{array}{l}
\left\{ \begin{array}{l}
4x - 3y = - 2\left( 1 \right)\\
2x + 5y = 12\left( 2 \right)
\end{array} \right.\\
\left( 1 \right) \Rightarrow 2x - \frac{3}{2}y = - 1\\
\Rightarrow 2x = \frac{3}{2}y - 1\,\\
Thay\,vào\,\left( 2 \right) \Rightarrow \frac{3}{2}y - 1 + 5y = 12\\
\Rightarrow \frac{{13}}{2}y = 13\\
\Rightarrow y = 2\\
\Rightarrow 2x = \frac{3}{2}y - 1 = 2\\
\Rightarrow x = 1\\
Vậy\,\left( {x;y} \right) = \left( {1;2} \right)
\end{array}$
