Đáp án:
c) x=1
Giải thích các bước giải:
\(\begin{array}{l}
b)\dfrac{5}{4} - \left| {x + \dfrac{3}{2}} \right| = 2019\\
\to \left| {x + \dfrac{3}{2}} \right| = - \dfrac{{8071}}{4}\left( l \right)\\
Do:\left| {x + \dfrac{3}{2}} \right| \ge 0\\
\to x \in \emptyset \\
c)3\left( {x - \dfrac{1}{2}} \right) = x + \dfrac{1}{2}\\
\to 3x - \dfrac{3}{2} = x + \dfrac{1}{2}\\
\to 2x = 2\\
\to x = 1
\end{array}\)
