| 3x - 5 | - | -$\frac{3}{2}$ | = 5
| 3x - 5 | - $\frac{3}{2}$ = 5
| 3x - 5 | = 5 + $\frac{3}{2}$
| 3x - 5 | = $\frac{13}{2}$
⇒ \(\left[ \begin{array}{l}3x-5=\frac{13}{2}\\3x-5=-\frac{13}{2}\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}3x=\frac{23}{2}\\3x=-\frac{3}{2}\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}x=\frac{23}{6}\\x=-\frac{1}{2}\end{array} \right.\)
Vậy x ∈ {$\frac{23}{6}$; -$\frac{1}{2}$}
