Đáp án: $\begin{array}{l} a)17\\b)10\\c)94\\d)42\\e)95\\f)500\\g)100\end{array}$
Giải thích:
$a)47-[(45.2^4-5^2.12):14]$
$=47-[(45.16-25.12):14]$
$=47-[(720-300):14]$
$=47-[420:14]$
$=47-30$
$=17$
$b)50-[(20-2^3):2+34]$
$=50-[(20-8):2+34]$
$=50-[12:2+34]$
$=50-[6+34]$
$=50-40$
$=10$
$c)10^2-[60:(5^6-5^4-3.5)]$
$=10^2-[60:(5^2-15)]$
$=10^2-[60:(25-15)]$
$=10^2-[60:10]$
$=100-6$
$=94$
$d)50-[(50-2^3.5):2+3]$
$=50-[(50-8.5):2+3]$
$=50-[(50-40):2+3]$
$=50-[10:2+3]$
$=50-[5+3]$
$=50-8$
$=42$
$e)128-[68+8(37-35)^2]:4$
$=128-[68+8.2^2]:4$
$=128-[68+8.4]:4$
$=128-[68+32]:4$
$=128-100:4$
$=120-25$
$=95$
$f)568-{5[143-(4-1)^2]+10}:10$
$=568-{5[143-3^2]+10}:10$
$=568-{5[143-9]+10}:10$
$=568-{5.134+10}:10$
$=568-{670+10}:10$
$=568-680:10$
$=568-68$
$=500$
$g)107-{38+[7.3^2-24:6+(9-7)^3]}:15$
$=107-{38+[7.9-4+2^3]}:15$
$=107-{38+[63-4+8]}:15$
$=107-{38+[59+8]}:15$
$=107-38+67:15$
$=107-105:15$
$=107-7$
$=100$
