Đáp án:g)$x=\frac{-28}{31}$
h)$x=\frac{-6}{19}$
Giải thích các bước giải:
g)$\frac{x-3}{11}+\frac{x+1}{3}=\frac{x+7}{9}-1$ (MC=297)
⇒$27(x-3)+99(x+1)=33(x+7)-297$
⇔$ 27x-81+99x+99=33x+231-297$
⇔$ 93x=-84⇔ x=\frac{-28}{31}$
h)$\frac{3x+0.4}{2}+\frac{1.5-2x}{3}=\frac{x+0.5}{5}$ (MC:30)
⇒$15(3x+0.4)+10(1.5-2x)=6(x+0.5)$
⇔$ 45x+6+15-20x=6x+3$
⇔ $19x=-6⇔ x=\frac{-6}{19}$