Đáp án + Giải thích các bước giải:
`a//x+(-23)=2.(-5)^{2}`
`->x-23=2.25`
`->x-23=50`
`->x=73`
`b//(8+x).(6-x)=0`
`→` \(\left[ \begin{array}{l}8+x=0\\6-x=0\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=-8\\x=6\end{array} \right.\)
Vậy `x∈{-8;6}`
`c//-12-(13-x)=(-5)^{2}`
`->-12-13+x=25`
`->x=25+12+13`
`->x=50`
`d//-63-|-x+(-24)|=-91`
`→|x-24|=-63-(-91)`
`→|x-24|=28`
`→x-24=±28`
`→` \(\left[ \begin{array}{l}x=52\\x=-4\end{array} \right.\)
Vậy `x∈{52;-4}`
`e//(x+10)^{2}-14=50`
`→(x+10)^{2}=64`
`->x+10=±8`
`→` \(\left[ \begin{array}{l}x=-2\\x=-18\end{array} \right.\)
Vậy `x∈{-2;-18}`
`g//45-(29+x)=x-(19-36)`
`→45-29-x=x-(-17)`
`→16-x=x+17`
`->-x-x=-16+17`
`→-2x=1`
`->x=-(1)/(2)`
