w) $\dfrac{2x-\dfrac{4-3x}{5}}{15} = \dfrac{7x-\dfrac{x-3}{2}}{5} -x+1$
$⇔ \dfrac{2x-\dfrac{4-3x}{5}}{15} = \dfrac{21x-\dfrac{3.(x-3)}{2}+15.(1-x)}{15}$
$⇔ 2x- \dfrac{4-3x}{5} = 21x-\dfrac{3.(x-3)}{2} + 15.(1-x)$
$⇔ 20x - 2.(4-3x) = 210x - 15.(x-3) +150.(1-x)$
$⇔26x -8 = 45x+195$
$⇔ -19x = 203$
$⇔x=\dfrac{-203}{19}$
a) $\dfrac{5.(x-1)+2}{6} - \dfrac{7x-1}{4} = \dfrac{2.(2x+1)}{7}-5$
$⇔ \dfrac{10.(x-1)+4-3.(7x-1)}{12} = \dfrac{2.(2x+1) - 35}{7}$
$⇔ 7.(10x-10+4-21x+3) = 12.(4x+2-35)$
$⇔7.(-11x-3) = 12.(4x-33)$
$⇔-77x -21 = 48x -396$
$⇔125x = 375$
$⇔x=3$
b) $x-\dfrac{3.(x+30)}{15} - 24\dfrac{1}{2} = \dfrac{7x}{10} - \dfrac{2.(10x+2)}{5}$
$⇔\dfrac{5x-x-30}{5} - \dfrac{49}{2} = \dfrac{7x-40x-8}{10}$
$⇔ \dfrac{8x-60 - 245}{10} = \dfrac{-33x-8}{10}$
$⇔41x = 297$
$⇔x=\dfrac{297}{41}$
