Đáp án:
b) 45 g
c) 62,5 ml
Giải thích các bước giải:
a) ${C_6}{H_{12}}{O_6}\xrightarrow{{men}}2C{O_2} + 2{C_2}{H_5}OH$
b)
$\begin{gathered}
{n_{C{O_2}}} = \dfrac{{11,2}}{{22,4}} = 0,5mol \hfill \\
\Rightarrow {n_{{C_6}{H_{12}}{O_6}}} = \dfrac{1}{2}{n_{C{O_2}}} = 0,25mol \hfill \\
\Rightarrow {m_{{C_6}{H_{12}}{O_6}}} = 0,25.180 = 45g \hfill \\
\end{gathered} $
c)
$\begin{gathered}
{n_{{C_2}{H_5}OH}} = {n_{C{O_2}}} = 0,5mol \hfill \\
\Rightarrow {m_{{C_2}{H_5}OH}} = 0,5.46 = 23g \hfill \\
\Rightarrow {V_{{C_2}{H_5}OH}} = \dfrac{m}{D} = \dfrac{{23}}{{0,8}} = 28,75ml \hfill \\
\Rightarrow {V_{dd{C_2}{H_5}OH}} = \dfrac{{28,75.100}}{{46}} = 62,5ml \hfill \\
\end{gathered} $
