`text{ta có}`
`(x+1)/111 = (y+2)/222 = (z+3)/333`
`=>(3x+3)/333 = (2y+4)/444 = (z+3)/333 `
`text{áp dụng tính chất dãy tỉ số bằng nhau}`
`=>(3x+3)/333=(2y+4)/444=(z+3)/333 = (3x+3+2y+4+z+3)/(333+444+333)=1110/1110 = 1`
`=>{((3x+3)/333=1),((2y+4)/444=1),((z+3)/333=1):}`
`=>{(3x+3=333),(2y+4=444),(z+3=333):}`
`=>{(x=110),(y=220),(z=330):}`
`text{Vậy x=110;y=220;z=330}`
~~~~~~~~~~~GOOD LUCK~~~~~~~~~~