Đáp án:
c. $\frac{2^7.9^3}{6^5.8^2} = \frac{2^7.(3^2)^3}{(2.3)^5.(2^3)^2} = \frac{2^7.3^6}{2^5.3^5.2^6} = \frac{2^7.3^6}{2^11.3^5} = \frac{3}{2^4} = \frac{3}{16}$
d. $\frac{6^3 + 3.6^2 + 3^3}{13} = \frac{2^3.3^3 + 3.2^2.3^2 + 3^3}{13} = \frac{3^3(2^3 + 2^2 + 1)}{13} = \frac{3^3(8 + 4 + 1)}{13} = \frac{3^3.13}{13} = 3^3 = 27$