Đáp án:
Giải thích các bước giải:
a )
$\frac{-1}{3}$ - $\frac{3}{4}$ + $\frac{1}{12}$
= $\frac{-1}{3}$ . $\frac{4}{4}$ - $\frac{3}{4}$ . $\frac{3}{3}$ + $\frac{1}{12}$
= $\frac{-1 . 4}{3 . 4}$ - $\frac{3 . 3}{4 . 3}$ + $\frac{1}{12}$
= $\frac{-4}{12}$ - $\frac{9}{12}$ + $\frac{1}{12}$
= $\frac{-4 - 9 + 1}{12}$
= $\frac{-12}{12}$
= -1
b )
$(1-\frac{3}{4})^{2}$ + |$\frac{-4}{5}$ | + $\frac{-29}{80}$ . $(-2019)^{0}$
= $(\frac{1}{4})^{2}$ + $\frac{4}{5}$ + $\frac{-29}{80}$ . 1
= $\frac{1}{16}$ + $\frac{4}{5}$ + $\frac{-29}{80}$
= $\frac{1}{16}$ . $\frac{5}{5}$ + $\frac{4}{5}$ . $\frac{16}{16}$ + $\frac{-29}{80}$
= $\frac{1 . 5}{16 . 5}$ + $\frac{4 . 16}{5 . 16}$ + $\frac{-29}{80}$
= $\frac{5}{80}$ + $\frac{64}{80}$ + $\frac{-29}{80}$
= $\frac{5 + 64 + (-29)}{80}$
= $\frac{40}{80}$
= $\frac{1}{2}$
c)
$\frac{-16}{15}$ . $\frac{3}{8}$ - $\frac{3}{8}$ . $\frac{-1}{15}$ + $\frac{11}{8}$
= $\frac{3}{8}$ . ( $\frac{-16}{15}$ - $\frac{-1}{15}$ ) + $\frac{11}{8}$
= $\frac{3}{8}$ . $\frac{-15}{15}$ + $\frac{11}{8}$
= $\frac{3}{8}$ . ( -1 ) + $\frac{11}{8}$
= $\frac{-3}{8}$ + $\frac{11}{8}$
= $\frac{-3 + 11}{8}$
= $\frac{8}{8}$
= 1
